4[4x-3(y-1)]=

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Solution for 4[4x-3(y-1)]= equation:


Simplifying
4[4x + -3(y + -1)] = 0

Reorder the terms:
4[4x + -3(-1 + y)] = 0
4[4x + (-1 * -3 + y * -3)] = 0
4[4x + (3 + -3y)] = 0

Reorder the terms:
4[3 + 4x + -3y] = 0
[3 * 4 + 4x * 4 + -3y * 4] = 0
[12 + 16x + -12y] = 0

Solving
12 + 16x + -12y = 0

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '-12' to each side of the equation.
12 + 16x + -12 + -12y = 0 + -12

Reorder the terms:
12 + -12 + 16x + -12y = 0 + -12

Combine like terms: 12 + -12 = 0
0 + 16x + -12y = 0 + -12
16x + -12y = 0 + -12

Combine like terms: 0 + -12 = -12
16x + -12y = -12

Add '12y' to each side of the equation.
16x + -12y + 12y = -12 + 12y

Combine like terms: -12y + 12y = 0
16x + 0 = -12 + 12y
16x = -12 + 12y

Divide each side by '16'.
x = -0.75 + 0.75y

Simplifying
x = -0.75 + 0.75y

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